0=36x^2-478-2463

Solution for 0=36x^2-478-2463 equation:

0=36x^2-478-2463

We move all terms to the left:

0-(36x^2-478-2463)=0

We add all the numbers together, and all the variables

-(36x^2-478-2463)=0

We get rid of parentheses

-36x^2+478+2463=0

We add all the numbers together, and all the variables

-36x^2+2941=0

a = -36; b = 0; c = +2941;
Δ = b2-4ac
Δ = 02-4·(-36)·2941
Δ = 423504
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{423504}=\sqrt{144*2941}=\sqrt{144}*\sqrt{2941}=12\sqrt{2941}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-12\sqrt{2941}}{2*-36}=\frac{0-12\sqrt{2941}}{-72}
=-\frac{12\sqrt{2941}}{-72}
=-\frac{\sqrt{2941}}{-6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+12\sqrt{2941}}{2*-36}=\frac{0+12\sqrt{2941}}{-72}
=\frac{12\sqrt{2941}}{-72}
=\frac{\sqrt{2941}}{-6}
$